x ≥ -3 or x ≤ 4
x ≥ 3 or x ≥ -4
x ≤ 3 or x v -4
x ≥ 3 or x ≤ -4
Correct answer is B
(x3 + x - 12) ≥ 0
(x + 4)(x - 3) ≥ 0
Either x + 4 ≥ 0 implies x ≥ -4
Or x - 3 ≥ 0 implies x ≥ 3
∴ x ≥ 3 or x ≥ -4
\(\begin{array}{c|c} x & 0 & 1\frac{1}{4} & 2 & 4\\ \hline y & 3 & 5...
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