In the diagram given, find the value of x.
A.
30o
B.
40o
C.
45o
D.
15o
Correct answer is B
In the diagram above, < CDE = < CED = 15o
(base < s of isos. \(\bigtriangleup\))
< ECD = 180o - (15 + 15)o
= 180o - 30o = 150o
But x + 110o = 150o
(Sum of opp. interior < s of a\(\bigtriangleup\) = opp. exterior < )
x = 150o - 110o = 40o