Two dice are tossed. What is the probability that the total score is a prime number.
A.
\(\frac{5}{12}\)
B.
\(\frac{5}{9}\)
C.
\(\frac{1}{6}\)
D.
\(\frac{1}{3}\)
Correct answer is A
Total possible outcome = 6 x 6 = 36
Required outcome = 15
∴ Pr(E) = \(\frac{15}{36} = \frac{5}{12}\)