John gives one-third of his money to Janet who has N105.00. He then finds that his money is reduced to one-fourth of what Janet now has. Find how much money john has at first

A.

N45.00

B.

N48.00

C.

N52.00

D.

N60.00

E.

N52.00

Correct answer is A

Let x be John's money, Janet already had N105, \(\frac{1}{3}\) of x was given to Janet

Janet now has \(\frac{1}{3^2}\)x + 105 = \(\frac{x + 315}{3}\)

John's money left = \(\frac{2}{3}\)x

= \(\frac{\frac{1}{4}(x + 315)}{3}\)

= \(\frac{2}{3}\)

24x = 3x + 945

∴ x = 45