In the diagram, PR is a diameter of the circle centre O. RS ...
In the diagram, PR is a diameter of the circle centre O. RS is a tangent at R and QPR = 58o. Find < QRS
A.
112o
B.
116o
C.
122o
D.
148o
Correct answer is C
PRQ = 90 - 58 = 32o(angle in a semi-circle)
Since PRS = 90o(radius angular to tangent)
QRS = 90 + 32
= 122o
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