\(\frac{9}{25} pr^2\)
\(\frac{9}{25} p^2r\)
\(\frac{25}{9} p^2r\)
\(\frac{25}{9} pr^2\)
Correct answer is C
p = \(\frac{3}{5} \sqrt{\frac{q}{r}}; \frac{5p}{3} = \sqrt{\frac{q}{r}}\)
= (\(\frac{5}{3}p\))2
= \(\frac{q}{r}\)
= \(\frac{25p^2}{9} = \frac{q}{r}\)
q = \(\frac{25}{9} p^2 r\)
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