A string of length 5cm is extended by 0.04m when a load of 0.8kg is suspended at the end. How far will it extend if a force of 16N is applied? [g = 10ms $^{-2}$ ]

0.04m

0.12m

0.01m

0.08m

Correct answer is D

From Hoke's Law, F = ke, K = Constant of Force

For he first case, Force = mg,

= 0.8 × 10 = 8N

∴ 8 = k × 0.04

k = $\frac{8}{0.04}$

= $\frac{200N}{m}$

Since K is constant

For the second case, F = ke

F = 200 × e

∴ e = $\frac{F}{200}$

= $\frac{16}{200}$

= 0.08m

See all Physics questions & answers

See more JAMB questions & answers

A string of length 5cm is extended by 0.04m when a load of 0.8kg is suspended at the end. How far will it extend if a force of 16N is applied? [g = 10ms $^{-2}$ ]

Similar Questions

Aptitude Tests

A string of length 5cm is extended by 0.04m when a load of 0.8kg is suspended at the end. How far will it extend if a force of 16N is applied? [g = 10ms−2^{-2}]

Similar Questions

Aptitude Tests

A string of length 5cm is extended by 0.04m when a load of 0.8kg is suspended at the end. How far will it extend if a force of 16N is applied? [g = 10ms $^{-2}$ ]