400mA
450mA
500mA
550mA
Correct answer is A
V = 0.1 x 50 x 10-3 = 5 x 10-3volts
RT = \(\frac{0.1 \times 0.0111}{0.1 + 0.0111}\)
= 9.99 x 10-3\(\Omega\)
V = IR \(\Rightarrow\) I
= \(\frac{5 \times 10^{-3}}{9.9 \times 10^{-3}}\)
= 0.5A ; = 500mA
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