An arrow of mass 0.1kg moving with a horizontal velocity of 15ms^-1 is shot into a wooden block of mass 0.4kg lying at rest on a smooth horizontal surface. Their common velocity after impact is

15.0 ms^-1

7.5 ms^-1

3.8 ms^-1

3.0 ms^-1

Correct answer is D

M₁U₁ + M₂U₂

= (m₁ + m₂)v

= \(\frac{(0.1 {\times} 15) + (0.4 {\times} 0)}{(0.1 + 0.4)}\)

v = 3ms^-1

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An arrow of mass 0.1kg moving with a horizontal velocity of 15ms-1 is shot into a wooden block of mass 0.4kg lying at rest on a smooth horizontal surface. Their common velocity after impact is