Write h in terms of a, b, c, d if a = \(\frac{b(1 - ch)}{a - dh}\)

A.

h = \(\frac{a - b}{ad}\)

B.

h = \(\frac{1 - b}{ad - bc}\)

C.

h = \(\frac{(a - b)^2}{ad - bc}\)

D.

h = \(\frac{a - b}{ad - bc}\)

E.

h = \(\frac{b - a}{ab - dc}\)

Correct answer is D

a = \(\frac{b(1 - ch)}{a - dh}\)

a = \(\frac{b - bch}{1 - dh}\)

= a - adh

= b - bch

a - b = bch + adn

a - b = adh

a - b = h(ad - bc)

h = \(\frac{a - b}{ad - bc}\)