h = a−bad
h = 1−bad−bc
h = (a−b)2ad−bc
h = a−bad−bc
h = b−aab−dc
Correct answer is D
a = b(1−ch)a−dh
a = b−bch1−dh
= a - adh
= b - bch
a - b = bch + adn
a - b = adh
a - b = h(ad - bc)
h = a−bad−bc
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