find the length XZ in the triangle
...
find the length XZ in the triangle
A.
√7m
B.
√6m
C.
√5m
D.
√3m
Correct answer is A
xz2 = xy2 + yx2 - 2(xy) (yz) cos 120o
= 22 + 12 - 2(2) (1) cos 1202
= 4 + 1 - 4x - cos 60 = 5 - 4x - 12
5 + 2 = 7
xz = √7m
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