In the diagram O is the center of the circle, if ∠QRS = 62o, find the value of ∠SQR.
A.
14o
B.
28o
C.
31o
D.
45o
E.
90o
Correct answer is B
< QSR = 90° (angle in a semi-circle)
\(\therefore\) < SQR = 180° - (90° + 62°)
= 28°