-5
-1
4
11
Correct answer is A
\(x = -\frac{1}{2}, y = 4\\ 3x^2y + xy^2\\ 3\left[-\frac{1}{2}\right]^2 \times 4 \times + \left(\frac{-1}{2}\right)(4)^2\\ 3\times \frac{1}{4} \times 4 -\frac{1}{2} \times 16\\ 3-8 = -5\)
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