Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

562.

Which of the following devices converts light energy to electrical energy?

A.

Bulb

B.

Television

C.

Solar cell

D.

Light emitting diode (LED)

Correct answer is C

The solar cell converts light from the sun to electricity.

563.

The diagram above illustrates a beaker of water being heated. It is observed that as the bubbles rise they get bigger in size.The reason for this observation is

A.

water pressure on the bubbles decreases

B.

density of water increases with rise in temperature

C.

volume of water increases with rise in temperature

D.

atmospheric pressure on the bubbles decreases

Correct answer is A

When a bubble is deep under water, it has both atmospheric pressure and water pressure (giving it depth), acting on it but as it rises, the water pressure decreases. At this point, the basic pressre acting on the bubble is the atmospheric pressure. Recall that pressure is inversely proportional to volume (Boyles' law), hence, the less the pressure, the more the volume

564.

A plane is inclined at an angle \(\theta\) to the horizontal. Its velocity ratio is

A.

\(sin\theta\)

B.

\(tan\theta\)

C.

\(\frac{1}{sin\theta}\)

D.

\(\frac{1}{tan\theta}\)

Correct answer is C

Velocity ratio = \(\frac{Effort distance}{Load distance}\)

On an inclined plane, it is the inverse of \(sin\theta\) = \(\frac{1}{sin\theta}\)

565.

Ice of mass 50g at 0°C was completely melted by 70% of the total heat energy supplied. Calculate the total heat energy supplied  [Specific latent heat of fusion of ice = 336\(Jg^{-1}\)]

A.

2400J

B.

6800J

C.

7251J

D.

24000J

Correct answer is D

The quantity of heat needed to melt ice = mL (where m is the mass of ice and L is the specific latent heat of fusion of ice)

Q = \(50 \times 336 = 16800J\) but this is 70% of the total heat supplied so that we have,

70% total heat = 16800J

\(\frac{70}{100}\) of total heat = 16800J

⇒ Total heat supplied = \(\frac{16800\times100}{70} = 24000J\)