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Ice of mass 50g at 0°C was completely melted by 70% o...

Ice of mass 50g at 0°C was completely melted by 70% of the total heat energy supplied. Calculate the total heat energy supplied  [Specific latent heat of fusion of ice = 336Jg1]

A.

2400J

B.

6800J

C.

7251J

D.

24000J

Correct answer is D

The quantity of heat needed to melt ice = mL (where m is the mass of ice and L is the specific latent heat of fusion of ice)

Q = 50×336=16800J but this is 70% of the total heat supplied so that we have,

70% total heat = 16800J

70100 of total heat = 16800J

⇒ Total heat supplied = 16800×10070=24000J