How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
For what values of x is the curve y = \(\frac{x^2 + 3}{x + 4}\) decreasing?
-3 < x \(\leq\) 0
-3 \(\geq\) x < 0
0 < x < 3
0 \(\leq\) x \(\leq\) 3
Correct answer is D
No explanation has been provided for this answer.
What is the solution of the equation x2 - x - 1 + 0?
x = 1.6 and x = -0.6
x = -1.6 and x = 0.6
x = 1.6 and x = 0.6
x = -1.6 and x = -0.6
Correct answer is A
\(x^{2} - x - 1 = 0\)
Using the quadratic formula,
\(x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}\)
a = 1, b = -1, c = -1.
\(x = \frac{-(-1) \pm \sqrt{(-1)^{2} - 4(1)(-1)}}{2(1)}\)
\(x = \frac{1 \pm \sqrt{1 + 4}}{2} = \frac{1 \pm \sqrt{5}}{2}\)
\(x = \frac{1 + 2.24}{2} ; x = \frac{1 - 2.24}{2}\)
\(x = \frac{3.24}{2}; x = \frac{-1.24}{2}\)
\(x = 1.62 ; x = -0.61 \)
\(x \approxeq 1.6; -0.6\)
Simplify \(\frac{x - y}{x^{\frac{1}{3}} - x^{\frac{1}{3}}}\)
x2 + xy + y2
x\(\frac{2}{3}\) + x \(\frac{1}{3}\) + y\(\frac{2}{3}\)
x\(\frac{2}{3}\) - x\(\frac{1}{3}\)y\(\frac{2}{3}\)
y\(\frac{2}{3}\)
Correct answer is B
No explanation has been provided for this answer.
Factorize completely \((x^2 + x)^2 - (2x + 2)^2\)
(x + 1)(x + 2)(x - 2)
(x + 1) 2(x + 2) (x - 2)
(x + 1)2 (x + 2)2
(x + 1)2 (x + 2)(x - 2)
Correct answer is D
\((x^{2} + x)^{2} - (2x + 2)^{2}\)
= \((x^{2} + x + 2x + 2)(x^{2} + x - (2x + 2))\)
= \((x^{2} + 3x + 2)(x^{2} - x - 2)\)
= \(((x + 1)(x + 2))((x + 1)(x - 2))\)
= \((x + 1)^{2} (x + 2)(x - 2)\)
If (g(y)) = \(\frac{y - 3}{11}\) + \(\frac{11}{y^2 - 9}\). what is g(y + 3)?
\(\frac{y}{11} + \frac{11}{y(y + 6)}\)
\(\frac{y}{11} + \frac{11}{y(y + 3)}\)
\(\frac{y + 30}{11} + \frac{11}{y(y + 3)}\)
\(\frac{y + 3}{11} + \frac{11}{y(y - 6)}\)
Correct answer is A
\(g(y) = \frac{y - 3}{11} + \frac{11}{y^{2} - 9}\)
\(\therefore g(y + 3) = \frac{(y + 3) - 3}{11} + \frac{11}{(y + 3)^{2} - 9}\)
\(g(y + 3) = \frac{y}{11} + \frac{11}{y^{2} + 6y + 9 - 9}\)
\(g(y + 3) = \frac{y}{11} + \frac{11}{y^{2} + 6y}\)
= \(\frac{y}{11} + \frac{11}{y(y + 6)}\)