x = 1.6 and x = -0.6
x = -1.6 and x = 0.6
x = 1.6 and x = 0.6
x = -1.6 and x = -0.6
Correct answer is A
\(x^{2} - x - 1 = 0\)
Using the quadratic formula,
\(x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}\)
a = 1, b = -1, c = -1.
\(x = \frac{-(-1) \pm \sqrt{(-1)^{2} - 4(1)(-1)}}{2(1)}\)
\(x = \frac{1 \pm \sqrt{1 + 4}}{2} = \frac{1 \pm \sqrt{5}}{2}\)
\(x = \frac{1 + 2.24}{2} ; x = \frac{1 - 2.24}{2}\)
\(x = \frac{3.24}{2}; x = \frac{-1.24}{2}\)
\(x = 1.62 ; x = -0.61 \)
\(x \approxeq 1.6; -0.6\)
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