(x + 1)(x + 2)(x - 2)
(x + 1) 2(x + 2) (x - 2)
(x + 1)2 (x + 2)2
(x + 1)2 (x + 2)(x - 2)
Correct answer is D
(x2+x)2−(2x+2)2
= (x2+x+2x+2)(x2+x−(2x+2))
= (x2+3x+2)(x2−x−2)
= ((x+1)(x+2))((x+1)(x−2))
= (x+1)2(x+2)(x−2)
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