How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Make y the subject of the formula Z = x\(^2\) + \(\frac{1}{y^3}\)
y = \(\frac{1}{(Z - x^2)^3}\)
y = \(\frac{1}{(Z + x^2)^{\frac{1}{3}}}\)
y = \(\frac{1}{(Z - x^2)^{\frac{1}{3}}}\)
y = \(\frac{1}{\sqrt[3]{Z} - \sqrt[3]{x^2}}\)
Correct answer is C
Z = x\(^2\) + \(\frac{1}{y^3}\)
Z - x\(^2\) = \(\frac{1}{y^3}\)
y\(^3\) = \(\frac{1}{Z - x^2}\)
y = \(\sqrt[3]{\frac{1}{Z - x^2}}\)
∴ y = \(\frac{1}{\sqrt[3]{Z - x^2}}\)
y = \(\frac{1}{(Z - x^2)^{\frac{1}{3}}}\)
P = 98R2
PR2 = 98
P = \(\frac{1}{98R2
P = \(\frac{PR2}{98}\)
Correct answer is B
P = \(\frac{1}{v}\) and vR2 = P = \(\frac{k}{v}\)......(i)
and v KR2 .......(ii)
(where k is constant)
Subst. for v in equation (i) = p = \(\frac{1^2}{KR}\).....(ii)
when r = 7, p = 2
2 = \(\frac{k}{7^2}\)
k = 2 x 49
= 98
Subt. foe k in ....(iii)
P = \(\frac{98}{R^2}\)
PR2 = 98
350k
200k
150k
50k
Correct answer is B
Q = 1.5 + 0.5n gives the cost 1(in Naira) of feeding n people for a week. Extra cost of feeding one additional person = n = 1 Subt. for n in the formula Q = 1.5 + 0.5(1) = 15 + 0.5 Q = N2 = 200k
If a u2 - 3v2 and b = 2uv + v2 evaluate (2a - b)(a - b2), when u = 1 and v = -1
9
15
27
33
Correct answer is A
a = u2 - 3y2 = (1)2 - 3(-1) = -2
b = 2uu + v2 + v2
= 2(1)(-1) + (-1)2 = -1
∴ 2(2a - b)(a - b∴) = [2(-2) - 1](-2 - (-1)2)
= -3 - 3
= 9
If P = \(\frac{2}{3}\) (\(\frac{1 - r^2}{n^2}\)), find n when r = \(\frac{1}{3}\) and p = 1
\(\frac{3}{2}\)
\(\frac{1}{3}\)
3
\(\frac{2}{3}\)
Correct answer is D
If P = \(\frac{2}{3}\) (\(\frac{1 - r^2}{n^2}\)), find n when r = \(\frac{1}{3}\) and p = 1
p = \(\frac{2(1 - r^2)}{3n^2}\) when r = \(\frac{1}{3}\) and p = 1
1 = \(\frac{2}{3}\) \(\frac{(1 - (\frac{1}{3})^2)}{n^2}\)
n2 = \(\frac{2(3 - 1)}{3 \times 3}\)
n2 = \(\frac{2 \times 2}{3 \times 3}\)
= \(\frac{4}{9}\)
n = \(\frac{4}{9}\)
= \(\frac{2}{3}\)