Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

1,421.

Every staff in an office owns either a Mercedes and/or a Toyota car. 20 own Mercedes, 15 own Toyota and 5 own both. How many staff are there in the office?

A.

25

B.

30

C.

35

D.

45

Correct answer is B

M = Mercedez; T = Toyota

Number of staff = 0 + (20 - 5) + (15 - 5) + 5

0 + 15 + 10 + 5 = 30

1,422.

In the diagram, find the size of the angle marked a°

A.

60o

B.

80o

C.

120o

D.

160o

Correct answer is B

2 x s = 280°(Angle at centre = 2 x < at circum)

S = \(\frac{280^o}{2}\)

= 140°

< O = 360 - 280 = 80°

60 + 80 + 140 + a = 360°

(< in a quad); 280 + a = 360

a = 360 - 280

a = 80°

1,423.

In the diagram, < QPR = 60o

< PQR = 50o

< QRS = 2xo

< SRP = 3xo

< UQP = yo and RS//TU

calculate y

A.

102o

B.

78o

C.

70o

D.

60o

Correct answer is A

< RQT = < QRS = 2x (Alternate angles). But in \(\bigtriangleup\) PRQ

50 + 60 + (2x + 3x) = 180o(Angles in a triangle)

110 + 5x = 180o

5x = 180o - 110 = 70o

x = \(\frac{70}{5}\) = 14o

Also y + 50 + 2(14) = 180o

y + 50 + 28 = 180o

y = 180 - 78

y = 102o

1,424.

In the diagram, PX is a tangent to the circle and RST is an equilateral triangle. Calculate < PTS

A.

60o

B.

90o

C.

120o

D.

150o

Correct answer is C

\(\bigtriangleup\) RST is equilateral triangle, hence

< TRS = < RTS = < RSt = 60o

But < PTR = 60o(Angle between a chord and a tangent at the point of contact = Angle in the alt. segment). From the diagram < PTS = < PTR + < RTS

= 60o + 60o = 120o

1,425.

If the perimeter of \(\bigtriangleup\)PQR in thr diagram is 24cm, what is the area of \(\bigtriangleup\)PRS?

A.

19.5cm2

B.

15.0cm2

C.

13.0cm2

D.

9.3cm2

Correct answer is B

Perimeter of \(\bigtriangleup\) PQR = PQ + QR + PR

24cm = 6cm + 8cm = PR

24 = 14 + PR

PR = 24 - 14 = 10cm

Area of \(\bigtriangleup\) PRS = \(\frac{1}{2} \times 10 \times 3cm^3\)

= 15cm3