In the diagram, < QPR = 60^o

< PQR = 50^o

< QRS = 2x^o

< SRP = 3x^o

< UQP = y^o and RS//TU

calculate y

102^o

78^o

70^o

60^o

Correct answer is A

< RQT = < QRS = 2x (Alternate angles). But in \(\bigtriangleup\) PRQ

50 + 60 + (2x + 3x) = 180^o(Angles in a triangle)

110 + 5x = 180^o

5x = 180^o - 110 = 70^o

x = \(\frac{70}{5}\) = 14^o

Also y + 50 + 2(14) = 180^o

y + 50 + 28 = 180^o

y = 180 - 78

y = 102^o

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In the diagram, < QPR = 60o < PQR = 50o < QRS = 2xo < SRP = 3xo < UQP = yo and RS//TU calculate y

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In the diagram, < QPR = 60^o

< PQR = 50^o

< QRS = 2x^o

< SRP = 3x^o

< UQP = y^o and RS//TU

calculate y