How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
190 sq.cm
20 sq.cm
210 sq.cm
160sq.cm
320sq.cm
Correct answer is C
By Pythagoras, KZ2 = 252 - 52
KZ2 = (25 + 15)(25 - 15) = 400
KZ = \(\sqrt{400}\) = 20
area of XYZ = \(\frac{1}{2} \times 28 \times 15\)
= 210 sq. cm
XYZ is a triangle and XW is perpendicular to YZ at = W. If XZ = 5cm and WZ = 4cm, Calculate XY.
5\(\sqrt{3}\)cm
3\(\sqrt{5}\)cm
3\(\sqrt{3}\)cm
5cm
6cm
Correct answer is B
by Pythagoras theorem, XW = 3cm
Also by Pythagoras theorem, XY2 = 62 + 32
XY2 = 36 + 9 = 45
XY = \(\sqrt{45} = 3 \sqrt{3}\)
In the figure, O is the centre of circle PQRS and PS//RT. If PRT = 135, then PSO is
67\(\frac{1}{2}\)o
22\(\frac{1}{2}\)o
33\(\frac{1}{2}\)o
45o
90o
Correct answer is D
< R = 180o - 45o (sum of angles on a straight line)
< R = < P = 45o (corresponding angles)
< PSO = < P = 45o (\(\bigtriangleup\)PSO is a right angle)
In the figure, TSP = PRQ, QR = 8cm, PR = 6cm and ST = 12cm. Find the length SP
4cm
16cm
9cm
14cm
Impossible, insufficient data
Correct answer is B
\(\frac{PQ}{6 + RT} = \frac{6}{12} = \frac{6}{PS}\)(Similar triangles)
\(\frac{6}{12} = \frac{8}{PS}\)
PS = \(\frac{12 \times 8}{6}\)
= 16cm
Find the x co-ordinates of the points of intersection of the two equations in the graph
1, 1
0, 4
0,0
4, 0
4, 9
Correct answer is D
If y = 2x + 1 and y = x2 - 2x + 1
then x2 - 2x + 1 = 2x + 1
x2 - 4x = 0
x(x - 4) = 0
x = 0 or 4