In the figure, TSP = PRQ, QR = 8cm, PR = 6cm and ST = 12cm. Find the length SP
4cm
16cm
9cm
14cm
Impossible, insufficient data
Correct answer is B
\(\frac{PQ}{6 + RT} = \frac{6}{12} = \frac{6}{PS}\)(Similar triangles)
\(\frac{6}{12} = \frac{8}{PS}\)
PS = \(\frac{12 \times 8}{6}\)
= 16cm
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