In the figure, O is the centre of circle PQRS and PS//RT. If PRT = 135, then PSO is
A.
67\(\frac{1}{2}\)o
B.
22\(\frac{1}{2}\)o
C.
33\(\frac{1}{2}\)o
D.
45o
E.
90o
Correct answer is D
< R = 180o - 45o (sum of angles on a straight line)
< R = < P = 45o (corresponding angles)
< PSO = < P = 45o (\(\bigtriangleup\)PSO is a right angle)