In △ XYZ, XKZ = 90O, XK = 15cm, XZ = 25cm and YK = 8cm. Find the area of △XYZ
190 sq.cm
20 sq.cm
210 sq.cm
160sq.cm
320sq.cm
Correct answer is C
By Pythagoras, KZ2 = 252 - 52
KZ2 = (25 + 15)(25 - 15) = 400
KZ = √400 = 20
area of XYZ = 12×28×15
= 210 sq. cm
Similar Questions
Find the value of x in 0.5x + 2.6 = 5x + 0.35 ...
Make x the subject of the equation s = 2 + t5(x + ⅗y)...
Factorize 9(x + y)2 - 4(x - y)2...
How many students scored at least 25% ...
The nth term of the progression 42, 73, 104, 135...
Find the simple interest rate percent annum at which N1000 accumulates to N1240 in 3 years. ...
In how many was can the letters of the word ELATION be arranged? ...
The expression x3 - 4x2 + cx + d is such that x + 1 is its factor, and its value is 1...
Find the value of log10 r + log10 r2 + log10 r4 + log10 r8 + log10 r16 + log10 r32 = 63...