WAEC Mathematics Past Questions & Answers - Page 80

396.

The scores of twenty students in a test are as follows: 44, 47, 48, 49, 50, 51, 52, 53, 53, 54, 58, 59, 60, 61, 63, 65, 67, 70, 73, 75. Find the third quartile.

A.

62

B.

63

C.

64

D.

65

Correct answer is C

Third quartile Q3 = \(\frac{3}{4}\)Nth

Alternatively:
Split the score into equal quarters

44, 47, 48, 49, 50,        51, 52, 53, 53, 54,         58, 59, 60, 61, 63,     65, 67, 70, 73, 75.

Third quartile Q3 = [63 + 65] / 2 = 64

397.

The population of students in a school is 810. If this is represented on a pie chart, calculate the sectoral angle for a class of 72 students

A.

32o

B.

45o

C.

60o

D.

75o

Correct answer is A

In a school with students' population 810, the sectoral angle for a class of 72 students is

= \(\frac{72}{810}\) x 360º

= 32º

398.

The angle of elevation of an aircraft from a point K on the horizontal ground 30\(\alpha\). If the aircraft is 800m above the ground, how far is it from K?

A.

400.00m

B.

692.82m

C.

923.76m

D.

1,600.99m

Correct answer is D

In \(\bigtriangleup\)KBC, sin 30 = \(\frac{800}{IKCI}\)

IKCL = \(\frac{800}{sin30^o}\)

= \(\frac{800}{0.5}\)

= 1600m

399.

PQRT is square. If x is the midpoint of PQ, Calculate correct to the nearest degree, LPXS

A.

53o

B.

55o

C.

63o

D.

65o

Correct answer is C

In the diagram given,

tan\(\alpha\) = \(\frac{1}{0.5}\) = 2

\(\alpha\) = tan - 1(2) = 63.43o

= 63o

400.

\(\begin{array}{c|c}
x & 0 & 1\frac{1}{4} & 2 & 4\\
\hline
y & 3 & 5\frac{1}{2} & &
\end{array}\)
The table given shows some values for a linear graph. Find the gradient of the line

A.

1

B.

2

C.

3

D.

4

Correct answer is B

Ler: (x1, y1) = (0, 3)

(x2, y2) = (\(\frac{5}{4}, \frac{11}{2}\))

Using gradient, m = \(\frac{y_2 - y_2}{x_2 - x_1}\)

= \(\frac{\frac{11}{2} - 3}{\frac{5}{4} - 0}\)

= \(\frac{11 - 6}{2} + \frac{5}{4}\)

= \(\frac{5}{} + \frac{5}{4}\)

= \(\frac{5}{2} \times \frac{4}{5}\)

= 2