$In the diagram, O is the centre, $\bar{RT}$ is a diameter, < PQT = 33$^o$ and <TOS = 76$^o$. Using the diagram, calculate the value of angle PTR.$

In the diagram, O is the centre, $\bar{RT}$ is a diameter, < PQT = 33 $^o$ and <TOS = 76 $^o$ . Using the diagram, calculate the value of angle PTR.

73^o

67^o

57^o

37^o

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Correct answer is C

In the diagram given, < PRT = 3 $^o$ (Change in same segment)

< TPR = 90 $^o$ (angle in a semicircle)

Hence, < PTR = 180 $^o$ - (90 + 33) $^o$

= 180 $^o$ - 123 $^o$

= 57 $^o$

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In the diagram, O is the centre, $\bar{RT}$ is a diameter, < PQT = 33 $^o$ and <TOS = 76 $^o$ . Using the diagram, calculate the value of angle PTR.

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In the diagram, O is the centre, ¯RT\bar{RT} is a diameter, < PQT = 33o^o and <TOS = 76o^o. Using the diagram, calculate the value of angle PTR.

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In the diagram, O is the centre, $\bar{RT}$ is a diameter, < PQT = 33 $^o$ and <TOS = 76 $^o$ . Using the diagram, calculate the value of angle PTR.