$In the diagram, O is the centre, $\bar{RT}$ is a diameter, < PQT = 33$^o$ and <TOS = 76$^o$. Using the diagram, calculate the value of angle PTR.$

In the diagram, O is the centre, $\bar{RT}$ is a diameter, < PQT = 33$^o$ and <TOS = 76$^o$. Using the diagram, calculate the value of angle PTR.

73^o

67^o

57^o

37^o

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Correct answer is C

In the diagram given, < PRT = 3$^o$ (Change in same segment)

< TPR = 90$^o$ (angle in a semicircle)

Hence, < PTR = 180$^o$ - (90 + 33)$^o$

= 180$^o$ - 123$^o$

= 57$^o$

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In the diagram, O is the centre, \(\bar{RT}\) is a diameter, < PQT = 33\(^o\) and <TOS = 76\(^o\). Using the diagram, calculate the value of angle PTR.

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