Loading [MathJax]/jax/output/HTML-CSS/jax.js

WAEC Mathematics Past Questions & Answers - Page 79

391.

In the diagram, VW//YZ, |WX| = 6cm, |XY| = 16cm, |YZ| = 20cm and |ZX| = 12cm. Calculate |VX|

A.

3cm

B.

4cm

C.

6cm

D.

8cm

Correct answer is D

In the diagram, 1612=VX6 (similar Δs)

VX = 16×612

= 8cm

392.

The probability that kebba, Ebou and Omar will hit a target are 23, 34 and 45 respectively. Find the probability that only Kebba will hit the target.

A.

25

B.

760

C.

130

D.

160

Correct answer is C

Hence the probability that only Kebba will hit the target

= P(K)xP(E')xP(O')

= 23×14×15

= 130

393.

Scores04591014Frequency212

The table shows the distribution of the scores of some students in a test. Calculate the mean scores.

A.

5.6

B.

6.2

C.

6.6

D.

7.0

Correct answer is D

To calculate the mean of grouped data,

- First step  to determine the midpoint (x) of each interval or class.

0 - 4 ►2

5 - 9  ► 7

 10 - 14  ►12

These midpoints must then be multiplied by the frequencies of the corresponding classes:

2 X 2 = 4 

1 X 7 = 7

2 X 12 = 24

Mean = ( 24 + 7 + 4) ÷ ( 2 + 1 + 2 )

: Mean = 7

394.

The scores of twenty students in a test are as follows: 44, 47, 48, 49, 50, 51, 52, 53, 53, 54, 58, 59, 60, 61, 63, 65, 67, 70, 73, 75. Find the third quartile.

A.

62

B.

63

C.

64

D.

65

Correct answer is C

Third quartile Q3 = 34Nth

Alternatively:
Split the score into equal quarters

44, 47, 48, 49, 50,        51, 52, 53, 53, 54,         58, 59, 60, 61, 63,     65, 67, 70, 73, 75.

Third quartile Q3 = [63 + 65] / 2 = 64

395.

The population of students in a school is 810. If this is represented on a pie chart, calculate the sectoral angle for a class of 72 students

A.

32o

B.

45o

C.

60o

D.

75o

Correct answer is A

In a school with students' population 810, the sectoral angle for a class of 72 students is

= 72810 x 360º

= 32º