WAEC Mathematics Past Questions & Answers - Page 74

366.

The roots of a quadratic equation are \(\frac{4}{3}\) and -\(\frac{3}{7}\). Find the equation

A.

21x2 - 19x - 12 = 0

B.

21x2 + 37x - 12 = 0

C.

21x2 - x + 12 = 0

D.

21x2 + 7x - 4 = 0

Correct answer is A

Let x = \(\frac{4}{3}\), x = -\(\frac{3}{7}\)

Then 3x = 4, 7x = -3

3x - 4 = 0, 7x + 3 = 0

(3x - 4)(7x + 3) = 0

21x2 + 9x - 28x - 12 = 0

21x2 - 19x - 12 = 0

367.

What sum of money will amount to D10,400 in 5 years at 6% simple interest?

A.

D8,000.00

B.

D10,000.00

C.

D12,000.00

D.

D16,000.00

Correct answer is A

A = P + 1

I = A - P

= 10,400 - P

Now using I = \(\frac{P \times T \times R}{100}\)

i.e. 10,400 - P = \(\frac{P \times 5 \times 6}{100}\)

= 100(10,400 - P) = 30P

10(10,400 - P) = 3P

104,000 - 10P = 3P

104,000 - 10P = 3P

104,000 = 3P + 10P

= 104,000 = 13P

P = \(\frac{104,000}{100}\)

P = D8,000

368.

Simplify; \(\frac{3^{n - 1} \times 27^{n + 1}}{81^{n}}\)

A.

32n

B.

9

C.

3n

D.

3n + 1

Correct answer is B

\(\frac{3^{n - 1} \times 27^{n + 1}}{81^{n}}\)

= \(\frac{3^{n - 1} \times 3^{3(n + 1)}}{3^{4n}}\)

= 3\(^{n - 1 + 3n + 3 - 4n}\)

= 3\(^{4n - 4n - 1 + 3}\)

= 32

= 9

369.

On a map, 1cm represent 5km. Find the area on the map that represents 100km2.

A.

2cm2

B.

4cm2

C.

8cm2

D.

8cm2

Correct answer is B

On a map, 1cm represents 5km. Then it follows that 1cm2 represents 25km2. Acm2 represents 100km2. By apparent cross-multiplication, 1cm2 x 100km2 = Acm2x 25km2

therefore A = \(\frac{100}{25}\) = 4cm2

370.

Which of following is a valid conclusion from the premise. "Nigeria footballers are good footballers"?

A.

Joseph plays football in Nigeria therefore he is a good footballer

B.

Joseph is a good footballer therefore he is a Nigerian footballer

C.

Joseph is a Nigerian footballer therefore he is a good footballer

D.

Joseph plays good football therefore he is a Nigerian footballer

Correct answer is C

From the venn diagram, Nigeria footballers from a subset of good footballers.