0.490g
0.049g
0.245g
0.0245g
Correct answer is C
Using
n = cv where n = no of mole, c = molar concentration(mol/dm3) and v = volume( dm3)
volume = 500\(cm^{3}\) = 0.5dm3, c = 0.005\(moldm^{-3}\)
number of mole(n) = c x v = 0.5 X 0.005 = 0.0025mol.
but n = \(\frac{mass}{ molar mass}\) = 0.0025 = \(\frac{mass}{ 98}\) (where 98g/mol is the molar mass of H2SO4)
mass of H2SO4 = 0.0025 x 98 = 0.245g.
a decrease in pressure
an increase in pressure
a decrease in temperature
an introduction of a positive catalyst
Correct answer is A
The equilibrium position is shifted to the left with a decrease in pressure in this system because the number of gaseous molecules on the right is less. (Le-Chatelier's principle).
Ethene is produced from ethanol by
decomposition
hydrolysis
ozonolysis
dehydration
Correct answer is D
Ethene can be gotten from the dehydration of ethanol in the presence of excess \(H_{2}SO_{4}\) or \(H_{3}PO_{4}\).
Consider the following reaction equation: \(Br_{2} + 2KI \to 2KBr + I_{2}\). Bromine is acting as
an oxidizing agent
a reducing agent
an acid
a base
Correct answer is A
No explanation has been provided for this answer.
\(C_{2}H_{4}\)
\(C_{3}H_{4}\)
\(C_{3}H_{6}\)
\(C_{4}H_{8}\)
Correct answer is C
Given the molecular formula, \(CH_{2}\).
The empirical formula will be \((CH_{2})n\)= 42
\((12+(2\times1))n =42\)
⇒ \(14n =42\)
n = 3, hence the empirical formula is \(C_{3}H_{6}\)