0.08\(gdm^{-3}\)
2.00\(gdm^{-3}\)
8.00\(gdm^{-3}\)
80.00\(gdm^{-3}\)
Correct answer is B
1000\(cm^{3}\) = 1\(dm^{3}\)
200\(cm^{3}\) = 0.2\(dm^{3}\)
⇒ 0.2\(dm^{3}\) contains 0.4g
hence, solubility of the salt which is the amount of the salt dissolvable in 1\(dm^{3}\) is
\(\frac{0.4g}{0.2dm^{3}} = 2.0gdm^{-3}\)