| Marks | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
| No of students | 5 | 7 | 9 | 6 | 3 | 6 | 4 |
The table above shows the distribution of marks by some candidates in a test. If a student is selected at random, what is the probability that she scored at least 6 marks?
340
14
1340
2740
Correct answer is C
No explanation has been provided for this answer.
| Marks | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
| No of students | 5 | 7 | 9 | 6 | 3 | 6 | 4 |
The table above shows the distribution of marks by some candidates in a test. Find, correct to one decimal place, the mean of the distribution.
5.5
5.3
5.2
4.7
Correct answer is D
| Marks(x | 2 | 3 | 4 | 5 | 6 | 7 | 8 | Total |
| Frequency f | 5 | 7 | 9 | 6 | 3 | 6 | 4 | 40 |
| fx | 10 | 21 | 36 | 30 | 18 | 42 | 32 | 189 |
Mean ˉx=∑fx∑f=18940
= 4.725≊
| Marks | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
| No of students | 5 | 7 | 9 | 6 | 3 | 6 | 4 |
The table above shows the distribution of marks by some candidates in a test. What is the median score?
3.5
4.0
4.5
5.0
Correct answer is B
No explanation has been provided for this answer.
Two forces F_{1} = (10N, 020°) and F_{2} = (7N, 200°) act on a particle. Find the resultant force.
(3 N, 020°)
(3 N, 200°)
(17 N, 020°)
(17 N, 200°)
Correct answer is A
No explanation has been provided for this answer.
\frac{1}{576}
\frac{55}{576}
\frac{77}{576}
\frac{167}{576}
Correct answer is D
P(Jide) = \frac{1}{12}; P(\text{not Jide}) = \frac{11}{12}
P(Atu) = \frac{1}{6}; P(\text{not Atu}) = \frac{5}{6}
P(Obu) = \frac{1}{8}; P(\text{not Obu}) = \frac{7}{8}
P(\text{only one of them}) = P(\text{Jide not Atu not Obu}) + P(\text{Atu not Jide not Obu}) + P(\text{Obu not Jide not Atu})
= (\frac{1}{12} \times \frac{5}{6} \times \frac{7}{8}) + (\frac{1}{6} \times \frac{11}{12} \times \frac{7}{8}) + (\frac{1}{8} \times \frac{11}{12} \times \frac{5}{6})
= \frac{35}{576} + \frac{77}{576} + \frac{55}{576}
= \frac{167}{576}