{4, 6, 8, 10}
{1. 4, 6, 8, 10}
{1, 2, 4, 6, 8, 10}
{1, 2, 3, 5, 7, 8, 9}
Correct answer is A
T = {2, 3, 5, 7}
M = {1, 3, 5, 7, 9}
\(\mu\) = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
T\(^{\prime}\) = = {1, 4, 6, 8, 9, 10}
M\(^{\prime}\) = {2, 4, 6, 8, 10}
(T\(^{\prime}\) \(\cap\) M\(^{\prime}\)) = {4, 6, 8, 10}
| Marks | 0 | 1 | 2 | 3 | 4 | 5 |
| Frequency | 7 | 4 | 18 | 12 | 8 | 11 |
The table gives the distribution of marks obtained by a number of pupils in a class test. Using this information, Find the median of the distribution
4
3
1
2
Correct answer is B
Median is \(\frac{n}{2} = \frac{6}{2}\)
= 3
Median = 3
Factorise (4a + 3) \(^2\) - (3a - 2)\(^2\)
(a + 1)(a + 5)
(a - 5)(7a - 1)
(a + 5)(7a + 1)
a(7a + 1)
Correct answer is C
[(4a + 3) \(^2\) - (3a - 2)\(^2\) = a\(^2\) - b\(^2\) = (a + b) (a - b)
= [(4a + 3) + (3a - 2)] [(4a + 3) - (3a - 2)]
= [4a + 3 + 3a - 2] [4a + 3 - 3a + 2]
= (7a + 1)(a + 5)
(a + 5) (7a + 1)
N9,700.00
N6,700.00
N2,000.00
N4,000.00
N2,300.00
Correct answer is E
Degree for food items = 360° - (120° + 80° + 43° + 30° + 18°)
= 360° - 291°
= 69°
∴∴ Amount spent on food items = \(\frac{69}{360}\)×12,000.00
= N2300.00
24\(^o\)
42\(^o\)
48\(^o\)
66\(^o\)
Correct answer is A
RSP = 90 < substance in semi a circle
RPS = 180 - (90 + 24)
= 180 - (114)
= 66
TPS = 180 - 66
= 114
RST = 24
< STR = 180 - (114 + 24)
= 180 - 138
= 42\(^o\)
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