24\(^o\)
42\(^o\)
48\(^o\)
66\(^o\)
Correct answer is A
RSP = 90 < substance in semi a circle
RPS = 180 - (90 + 24)
= 180 - (114)
= 66
TPS = 180 - 66
= 114
RST = 24
< STR = 180 - (114 + 24)
= 180 - 138
= 42\(^o\)
If log\(_{x^{1/2}}^{64}\) = 3, find the value of x ...
In the diagram, PR is a tangent to the circle at Q, QT//RS, ...
Ladi sold a car for N84,000 at a loss of 4%. How much did ladi buy the car? ...
Evaluate without using tables (0.008) -\(\frac{1}{3}\) x (0.16) - \(\frac{3}{2}\)...
O is the centre of the circle PQRS. PR and QS intersect at T POR is a diameter, ∠PQT = 42o and ∠...