In the diagram above, what is the size of angle ACB?
40o
50o
60o
80o
100o
Correct answer is C
< ABC = 80° (alternate angles)
< ACB = 180° - (80° + 40°) = 60°
Simplify \(\frac{9^{-\frac{1}{2}}}{27^{\frac{2}{3}}}\)
1
1/3
1/9
1/18
1/27
Correct answer is E
\(\frac{9^{-\frac{1}{2}}}{27^{\frac{2}{3}}}\)
=\(\frac{3^{-1}}{3^2}\) = \(\frac{1}{27}\)
In the diagram above O is the center of the circle, if ∠PAQ = 75o, what is the value of ∠PBQ?
15o
75o
105o
150o
210o
Correct answer is C
< PBQ = 180° - 75° (opp angles of a cyclic quadrilateral)
= 105°
2
7
8
9
10
Correct answer is B
No explanation has been provided for this answer.
2
7
8
9
10
Correct answer is C
No explanation has been provided for this answer.