In the diagram above, PQRS is a cyclic quadrilateral, ∠PSR = 86o and ∠QPR = 38o. Calculate PRQ
58o
53o
48o
43o
38o
Correct answer is C
PQR = 180o - 86o = 94o
∴PRQ = 180o - 94o - 36o = 48o
Which triangle is equal in area to ΔVWZ
ΔVXZ
ΔVYZ
ΔXYV
ΔWYV
ΔWYZ
Correct answer is B
Area of \(\Delta\) VYZ = Area of \(\Delta\) VWZ (same base and within same parallel)
∠VXZ
∠VYX
∠XZW
∠YXZ
∠VYW
Correct answer is A
< VWZ = < VXZ (angles in the same segment)
In the diagram above PS||RQ, |RQ| = 6.4cm and perpendicular PH = 3.2cm. Find the area of SQR
5.12cm2
9.60cm2
10.24cm2
20.48cm2
40.96cm2
Correct answer is C
Area of a triangle = \(\frac{1}{2} \times b \times h\)
Area of \(\Delta\) SQR = \(\frac{1}{2} \times 6.4 \times 3.2\)
= 10.24 cm\(^2\)
In the diagram above, WXYZ is a rhombus and ∠WYX = 20°. What is the value of ∠XZY
20o
30o
45o
60o
70o
Correct answer is E
Diagonals bisect at 90°; < YXZ = 90° - 20° = 70°
But ZY = XY (sides of a rhombus)
\(\therefore\) < XYZ = 70° (base angle of an isos. triangle)
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