Find the value of m which makes x\(^2\) + 8 + m a perfect square
2
4
8
12
16
Correct answer is E
x\(^2\) + 8 + m
To make it a perfect square, we add \((\frac{b}{2})^2\)
= \((\frac{8}{2})^2\)
= 16
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