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WAEC Mathematics Past Questions & Answers - Page 315

1,571.

Use mathematical table to evaluate (cos40° - sin30°)

-0.2660

-0.0266

0.0266

0.2660

1.5320

View answer & explanation

Correct answer is D

(cos 40° - sin 30°)

= 0.7660 - 0.5

= 0.2660

1,572.

Which of the sketches above gives a correct method for constructing an angle of 120^o at the point P?

I only

II only

III only

I and II only

I, II and III

View answer & explanation

Correct answer is D

No explanation has been provided for this answer.

1,573.

In the diagram above, PQ is a tangent at T to the circle ABT. ABC is a straight line and TC bisects ∠BTO. Find x.

20^o

30^o

35^o

40^o

50^o

View answer & explanation

Correct answer is E

From the figure < TAB = < BTQ = 40° (alternate segment)

$\therefore$ < ATB = 180° - (70° + 40°) = 70° (angle on a straight line)

< BTC = $\frac{40°}{2} = \frac{< BTQ}{2}$

$\therefore < BTQ = 40°$

x° = 180° - (40° + 70° + 20°)

= 50°

1,574.

In the diagram below, O is the center of the circle if ∠QOR = 290^o, find the size ∠QPR

110^o

70^o

55^o

35^o

20^o

View answer & explanation

Correct answer is D

360^o - 290^o = 70^o
70/2 = 35^o

1,575.

In the diagram above, PQRS is a cyclic quadrilateral, ∠PSR = 86^o and ∠QPR = 38^o. Calculate PRQ

58^o

53^o

48^o

43^o

38^o

View answer & explanation

Correct answer is C

PQR = 180^o - 86^o = 94^o
∴PRQ = 180^o - 94^o - 36^o = 48^o

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