In the diagram above, PQ is a tangent at T to the circle ...
In the diagram above, PQ is a tangent at T to the circle ABT. ABC is a straight line and TC bisects ∠BTO. Find x.
20o
30o
35o
40o
50o
Correct answer is E
From the figure < TAB = < BTQ = 40° (alternate segment)
∴< ATB = 180° - (70° + 40°) = 70° (angle on a straight line)
< BTC = \frac{40°}{2} = \frac{< BTQ}{2}
\therefore < BTQ = 40°
x° = 180° - (40° + 70° + 20°)
= 50°
Similar Questions
Which of the following statements is true from the diagram above? ...
Factorize 9p^2 - q^2 + 6qr - 9r^2...
Find the range of values of x which satisfy the inequalities 4x - 7 \leq 3x and 3x - 4 \leq ...
If x3 - 12x - 16 = 0 has x = -2 as a solution then the equaion has...
The angles marked in the diagram above are measured in degrees. Find x ...
If 85% of x is N3230, what is the value of x? ...