WAEC Mathematics Past Questions & Answers - Page 306

1,527.

A box contains 2 white and 3 blue identical marbles. If two marbles are picked at random, one after the other without replacement, what is the probability of picking two marbles of different colors?

A.

2/3

B.

3/5

C.

2/5

D.

7/20

E.

3/10

Correct answer is B

Total number of marbles = 5; 1st pick = 2/5 2nd pick = 3/4; 3rd pick = 3/5; 4th pick = 2/4
∴ Probability of picking two marbles of different colors = (2/5 x 3/4) + (3/5 + 2/4) = 12/20 = 3/5

1,528.

If events X and Y are mutually exclusive, P(X) = 1/3 and P(Y) = 2/5, P(X∪Y) is

A.

0

B.

2/15

C.

4/14

D.

11/15

E.

1

Correct answer is D

P(X \(\cup\) Y) = \(\frac{1}{3} + \frac{2}{5}\)

= \(\frac{11}{15}\)

1,529.

If events X and Y are mutually exclusive, . P(X) = 1/3 and P(Y) = 2/5, P(X∩Y) is

A.

0

B.

2/15

C.

11/15

D.

4/15

E.

1

Correct answer is B

P(X \(\cap\) Y) = \(\frac{1}{3} \times \frac{2}{5}\)

= \(\frac{2}{15}\)

1,530.

The mean of 30 observations recorded in an experiment is 5. lf the observed largest value of 34 is deleted, find the mean of the remaining observations

A.

5

B.

4

C.

3.9

D.

3.4

E.

3.0

Correct answer is B

x = 5, \(\frac{\sum {fx}}{\sum {f}}\) =

5= \(\frac{\sum {fx}}{30}\)

\(\sum {fx}\) = 5 x 30 = 150; 150 - 34 = 116

\(\sum {f}\) = 29
\(\sum {fx}\) = 116

= \(\frac{116}{29}\) = 4