\(-\frac{1}{2}\)
\(-\frac{\sqrt{3}}{2}\)
\(\frac{1}{2}\)
\(\frac{\sqrt{2}}{2}\)
\(\frac{\sqrt{3}}{2}\)
Correct answer is A
sin 210 = - sin (210 - 180) = - sin 30
= \(-\frac{1}{2}\)
1
√2/2
0
-1
-√2/2
Correct answer is D
tan 315° = - tan (360 - 315) = - tan 45 = -1
If cos θ = 5/13, what is the value of tan \(\theta\) for 0 < θ < 90° ?
13
5
13/5
12/5
5/12
Correct answer is D
\(\cos \theta = \frac{5}{13}\)
\(\implies\) In the right- angled triangle, with an angle \(\theta\), the adjacent side to \(\theta\) = 5 and the hypotenuse = 13.
\(\therefore 13^2 = opp^2 + 5^2\)
\(opp^2 = 169 - 25 = 144 \implies opp = \sqrt{144}\)
= 12.
\(\tan \theta = \frac{opp}{adj} = \frac{12}{5}\)
Sin 60° has the same value as
I. Sin 120°
II. cos 240°
III. -sin 150°
IV. cos 210°
V. sin 240°
I only
II only
IV only
III only
IV and V only
Correct answer is A
In the second quadrant, \(\sin 120 = \sin (180 - 120)\)
= \(\sin 60\)
20o
50o
55o
70o
75o
Correct answer is C
< PTQ = 25° (base angles of an isos. triangle)
\(\therefore\) < PQT = 180° - (25° + 25°) = 130° (sum of angles in triangle PQT)
\(\therefore\) < RST = 130° - 75° = 55° (exterior angle = sum of 2 opp. interior angles)
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