Given that 2p - m = 6 and 2p + 4m = 1, find the value of (4p + 3m).
1
3
5
7
9
Correct answer is D
2p - m = 6 ... (i) 2p + 4m = 1 ... (ii) From (i), m = 2p - 6. 2p + 4(2p - 6) = 1 2p + 8p - 24 = 1 10p = 1 + 24 = 25 p = 2.5 m = 2(2.5) - 6 = 5 - 6 = -1 ∴ 4p + 3m = 4(2.5) + 3(-1) = 10 - 3 = 7
Given that 2p - m = 6 and 2p + 4m = 1, find the value of (4p + 3m).
1
3
5
7
9
Correct answer is D
2p - m = 6 ... (i) 2p + 4m = 1 ... (ii) From (i), m = 2p - 6. 2p + 4(2p - 6) = 1 2p + 8p - 24 = 1 10p = 1 + 24 = 25 p = 2.5 m = 2(2.5) - 6 = 5 - 6 = -1 ∴ 4p + 3m = 4(2.5) + 3(-1) = 10 - 3 = 7
(12)
(4, 8, 16, 20)
(3, 6, 9, 15, 18)
(1,2,5,7,10,11,13,17,19)
(3, 4, 6, 8, 9, 12, 15, 16, 18, 20)
Correct answer is B
E = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20}
P = {3, 6, 9, 12, 15, 18}
Q = {4, 8, 12, 16, 20}
P' = {1, 2, 4, 5, 7, 8, 10, 11, 13, 14, 16, 17, 19, 20}
P' \(\cap\) Q = {4, 8, 16, 20}
11
20
21
22
24
Correct answer is B
\(T_{n} = a + (n - 1) d\) (terms of an A.P)
\(T_{1} = a\)
\(T_{2} = a + d\)
\(T_{10} = a + 9d\)
\(a + a + d = 2a + d = 4 ... (i)\)
\(a + 9d = 19 ... (ii)\)
(ii) x 2: \(2a + 18d = 38 ... (iii)\)
(iii) - (i) : \(17d = 34 \implies d = 2\)
\(2a + 2 = 4 \implies 2a = 2\)
\(a = 1\)
\(T_{5} + T_{6}\)
= \((a + 4d) + (a + 5d)\)
= \(2a + 9d\)
= \(2(1) + 9(2)\)
= 20
A string is 4.8m. A boy measured it to be 4.95m. Find the percentage error.
\( \frac{5}{16} \)%
\(1\frac{5}{16} \)%
\( 3\frac{1}{33} \)%
\( 3\frac{1}{8} \)%
25%
Correct answer is D
4.95m - 4.8m = 0.15m
\(\frac{0.15}{4.8} \times 100%\)
= \(\frac{25}{8}\)
= \(3\frac{1}{8}\)%