0.117
0.118
0.903
0.944
0.946
Correct answer is A
log10 x = ˉ2.3675 => x = 0.023
log10 y = ˉ2.9738 => y = 0.094
x + y = 0.117
In the diagram above, AO is perpendicular to OB. Find x
7.5o
15o
22.5o
30o
38.6o
Correct answer is D
4x + 3x + 2x + 90 =360° [angle at a point]
9x + 90 = 360°
9x = 360° - 90°
9x = 270
x = 270/9
x = 30°
In the diagram above; O is the centre of the circle and |BD| = |DC|. If ∠DCB = 35°, find ∠BAO.
20o
25o
30o
35o
40o
Correct answer is A
< DBC = 35° (base angles of an isosceles triangle)
< CDB = 180° - (35° + 35°)
= 110°
< ADB = 70°; < ADB = 90°
∴ < BAO = 180° - (70° + 90°)
= 20°