In the diagram above; O is the centre of the circle and |BD| = |DC|. If ∠DCB = 35°, find ∠BAO.
A.
20o
B.
25o
C.
30o
D.
35o
E.
40o
Correct answer is A
< DBC = 35° (base angles of an isosceles triangle)
< CDB = 180° - (35° + 35°)
= 110°
< ADB = 70°; < ADB = 90°
\(\therefore\) < BAO = 180° - (70° + 90°)
= 20°