find the first quartile of 7,8,7,9,11,8,7,9,6 and 8.
8.5
7.0
7.5
8.0
Correct answer is B
Rearrange data in increasing order: 6,7,7,7,8,8,8,9,9 and 11
First quartile (ungrouped data) = \(\frac{n}{4}\)th value
= \(\frac{10}{4}\)
= 2.5th value
= \(\frac{7 + 7}{2}\)
= 7.0
130°
115°
58°
68°
Correct answer is C
Alternate segments are equal : R° = 64°
An isosceles triangle has two angles ( Q° & N° ) equal as A°
R° + A° + A° = 180°
2A°= 180 - 64
2A° = 116°
A = \(\frac{116}{2}\)
A = 58.
: Q° = 58, N° = 58 and T° = 58
As Alternate segments are equal: T = Q
215°
70°
135°
145°
Correct answer is A
sum of angle in a straight line = 180°
35 + m = 180
m = 180 - 35 = 145°
Corresponding angles are congruent i.e equal to each other
Angle X and M are congruent = 145
sum of angle in a straight line = 180°
110 + n = 180
m = 180 - 110 = 70°
Angle Y and N are congruent = 70°
∴∴ ( x + y) = ( 145 + 70)°
(x + y) = 215°
3.71
3.70
3.69
3.72
Correct answer is A
The mean = sum of 1\(\frac{1}{2}\), 2\(\frac{2}{3}\), 3\(\frac{3}{4}\), 4\(\frac{4}{5}\), and 5\(\frac{5}{6}\) divided by their quantity.
Mean = ( 1\(\frac{1}{2}\) + 2\(\frac{2}{3}\) + 3\(\frac{3}{4}\) + 4\(\frac{4}{5}\) + and 5\(\frac{5}{6}\) ) / 5
= 3.708 or 3.71( 2 d.p )
84cm\(^2\)
80cm\(^2\)
30cm\(^2\)
94cm\(^2\)
Correct answer is B
Area of circle = πr\(^2\) = \(\frac{22}{7}\) * 7\(^2\) = 154cm\(^2\)
Area o Trapezium = \(\frac{(a + b) h}{2}\) = \(\frac{(10 + 21)8}{2}\) = 124cm\(^2\)
Area of the region not covered = Area of (Circle - Trapezium)
= 154 - 124
= 30cm\(^2\)
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