130°
115°
58°
68°
Correct answer is C
Alternate segments are equal : R° = 64°
An isosceles triangle has two angles ( Q° & N° ) equal as A°
R° + A° + A° = 180°
2A°= 180 - 64
2A° = 116°
A = \(\frac{116}{2}\)
A = 58.
: Q° = 58, N° = 58 and T° = 58
As Alternate segments are equal: T = Q