y = o or 3
y = 0 or 9
y = -3 or 3
y = 3 or 9
Correct answer is B
3y2=27y3y2−27y=03y(y−9)=03y=0ory−9=0y=0ory=9y=0or9
Make t the subject of formula k=m√t−pr
rk2+pm2
rk2+pm2m2
rk2−pm2
rk2−p2m2
Correct answer is B
k=m√t−pr
km=√t−pr
(km)2=t−pr
rk2=m2(t−p)
∴
t = \frac{rk^2 + m^2 p}{m^2}
Find the equation whose roots are -8 and 5
x^2 + 13x + 40=0
x^2 - 13x - 40=0
x^2 - 3x +40=0
x^2 + 3x - 40=0
Correct answer is D
Equation with roots -8 and 5: (x + 8)(x - 5) = 0
x^2 - 5x + 8x - 40 = 0
x^2 + 3x - 40 = 0
Form an inequality for a distance d meters which is more than 18m, but not more than 23m
18 ≤ d ≤ 23
18 < d ≤ 23
18 ≤ d < 23
d < 18 or d > 23
Correct answer is B
No explanation has been provided for this answer.
Simplify \frac{1}{x-3}-\frac{3(x-1)}{x^2 - 9}
\frac{x-1}{x-3}
\frac{-2}{x+3}
\frac{x-1}{x+3}
\frac{4x}{x^2-9}
Correct answer is B
\frac{1}{x-3}-\frac{3(x-1)}{x^2 - 9}\\ \frac{1}{x-3}-\frac{3(x-1)}{(x-3)(x+3)}\\ \frac{x+3-3x+3}{(x-3)(x+3)};\frac{-2x+6}{(x-3)(x+3)}\\ \frac{-2(x-3)}{(x-3)(x+3)}=\frac{-2}{x+3}