Express 25° 45' in decimal (Hint: 1° = 60')
25.75o
25.55o
25.45o
25.15o
Correct answer is A
25° 45' = 25° + 4560°
= 25° + 0.75°
= 25.75°
5.0km
7.5km
7.6km
8.7km
Correct answer is D
(PR)2=(PQ)2+(QR)2
102=52+(QR)2
(QR)2=100−25
QR=√75
= 8.660
≊ 8.7 km
Given that sin P = \frac{5}{13}, where p is acute, find the value of cos p - tan p
\frac{79}{156}
\frac{85}{156}
\frac{7}{13}
\frac{8}{1}
Correct answer is A
If sin P = \frac{5}{13} from right angled triangle from pythagoras theorem
BC^2 = 13^2 - 5^2\\
=169-25\\
BC = \sqrt{144} = 12\\
∴ cos P - tan P = \frac{12}{13} - \frac{5}{12}\\
=\frac{79}{156}
The bearing S40°E is the same as
040o
050o
130o
140o
Correct answer is D
= 90° + 50°
= 140°
If 2x : (x +1) = 3:2, what is the value of x?
\frac{1}{2}
1
1\frac{1}{2}
3
Correct answer is D
2x : (x + 1) = 3:2\\ \frac{2x}{x+1}=\frac{3}{2}\\ ∴ 4x = 3x + 3 x =3
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