Given that sin P=513, where p is acute, find ...
Given that sin P=513, where p is acute, find the value of cos p - tan p
A.
79156
B.
85156
C.
713
D.
81
Correct answer is A
If sinP=513 from right angled triangle from pythagoras theorem
BC^2 = 13^2 - 5^2\\
=169-25\\
BC = \sqrt{144} = 12\\
∴ cos P - tan P = \frac{12}{13} - \frac{5}{12}\\
=\frac{79}{156}
Similar Questions
Find the inter-quartile range of 1, 3, 4, 5, 8, 9, 10, 11, 12, 14, 16 ...
Find the value of x at the minimum point of the curve y = x3 + x2 - x + 1 ...
Simplify 2\sqrt{3} - \frac{6}{\sqrt{3}} + \frac{3}{\sqrt{27}}...
The volume of a cube is 512cm3. Find the length of its side...
A point X is on the bearing 342° from a point Y. What is the bearing of Y from X? ...
If m * n = n - (m+2) for any real number m and n find the value of 3*(-5)? ...