Given that F1(x) = x3√x, find f(x)
2x9/29+c
2x9/2+c
2x5/25+c
x4+c
Correct answer is A
F1 (x) = x3 √x = x7/2
F(x) = x7/2+17/2+1 + c
= x9/29/2
= 2x9/29 + c
Calculate the distance travelled in the third second.
5.5m
14.5m
26.0m
30.0m
Correct answer is A
From S = 12t + 52t2 - t3;
Distance traveled in 2 seconds
S = 12[2] + 52[2]2 - 23.
= 24 + 10 - 8 = 26m
Distance traveled in 3 seconds
S = 12[3] + 52[3]2 - 33
= 36 + 22.5 - 27 = 31.5m
Distance traveled in the 3rd second
= 31.5m - 26m
: S = 5.5m
Calculate the maximum height reached.
418.5m
56.0m
31.5m
30.0m
Correct answer is C
S = 12t + 52t2 - t3;
ds/dt = 12 + 5t - 3t2
At max height ds/dt = 0
i.e 12 + 5t - 3t2
(3t + 4)(t -3) = 0;
t = -4/3 or 3
Hmax = 12[3] + 52[3]2 - 33
= 36 + 45/2 - 27
= 31.5m
In △PQR, ¯PQ = 5i - 2j and ¯QR = 4i + 3j. Find ¯RP
-i - 5j
-9 - j
i + 5j
-9i + j
Correct answer is A
¯PQ = 5i - 2j; ¯QR = 4i + 3j
¯RP = ¯PQ - ¯QR
= 5i - 2j - [4i + 3j] = 5i - 2j - 4i - 3j
= i - 5j
5√3
6√2
6√3
9√3
Correct answer is C
No explanation has been provided for this answer.